Step-by-step explanation:
The reaction between Cu²⁺ and Na₂CO₃ will be:
Cu²⁺ (aq) + Na₂CO₃ (aq) ----> CuCO₃ (s) + 2 Na⁺ (aq) molecular equation
Where all the species are soluble except for CuCO₃ that is an insoluble compound and will form a precipitate.
Before we find the net ionic equation we have to write the total ionic equation. To do that we have to split the soluble compounds into its ions.
Cu²⁺ (aq) + 2 Na⁺ (aq) + CO₃²⁻ (aq) ----> CuCO₃ (s) + 2 Na⁺ (aq) total ionic equation
And to get the net ionic equation we have to identify the spectator ions and cancel them. Spectator ions are the ones that don't participate in the reaction, they are present on both sides of the reaction. The only spectator ion in this equation is Na⁺. If we cancel it from both sides of the equation we get the net ionic equation.
Cu²⁺ (aq) + CO₃²⁻ (aq) ----> CuCO₃ (s) net ionic equation
Answer: Cu²⁺ (aq) + CO₃²⁻ (aq) ----> CuCO₃ (s)