Question

Write the standard equation of the circle with center (-8, -7) and a radius of 6.

Answer 1

`\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad \begin{array}{lllll} center\ (&{{ h}},&{{ k}})\qquad radius=&{{ r}}\\ &-8&-7&6 \end{array}`

Answer 2

Standard form:
(x - h)^2 + (y - k)^2 = r^2
(h, k) is the center and r is the radius
(x - - 8)^2 + (y - - 7)^2 = 6^2
(x + 8)^2 + (y + 7)^2 = 36