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Which equation represents this line in point-slope form? (-3,4) and (3,-4) A . ( y + 4) = 4/3 (x + 3) B . ( y - 4) = - 4/3 (x + 3) C . y = - 3/4x B . 4y - 3x = 0

Which equation represents this line in point-slope form? (-3,4) and (3,-4) A . ( y + 4) = 4/3 (x + 3) B . ( y - 4) = - 4/3 (x + 3) C . y = - 3/4x B . 4y - 3x = 0
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2 votes
Which equation represents this line in point-slope form? (-3,4) and (3,-4)

A . ( y + 4) = 4/3 (x + 3)

B . ( y - 4) = - 4/3 (x + 3)

C . y = - 3/4x

B . 4y - 3x = 0

User Deepak Goyal
by
8.2k points

2 Answers

3 votes
so i'm guessing by what he says thats the last one
User Jeremy Gosling
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8.5k points
4 votes

\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -3}}\quad ,&{{ 4}})\quad % (c,d) &({{ 3}}\quad ,&{{ -4}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-4-4}{3-(-3)}\implies \cfrac{-4-4}{3+3}


\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad \begin{array}{llll} \textit{plug in the values for } \begin{cases} y_1=4\\ x_1=-3\\ m=\boxed{?} \end{cases}\\ \end{array}\\ \left. \qquad \right. \uparrow\\ \textit{point-slope form}
User Braden Brown
by
8.4k points
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