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3 votes
If f(x)=x^2+7, what is the equation for f^-1(x)???

2 Answers

3 votes
So...
f(x)=x^2+7
Consider the output as being y.
y=x^2+7
Thinking of this as a step-by-step procedure (namely , take a number x , square it and then add 7 ) , to reverse this , we have to solve for x the equation y=x^2+7 .

y=x^2+7
x^2=y-7


x=\pm√(y-7)


\implies f^(-1)(x)=\pm√(y-7)

I think the answer is correct now...
User Chintan Khetiya
by
8.7k points
5 votes
Given: f(x) = x² + 7

Let y = x² + 7
x = y² + 7 (since the inverse is reflected about the y = x line, the coordinates are interchangeable)

y² = x - 7
y = √(x - 7)

Thus, the inverse function f^(-1)x = √(x - 7)
User Jacoblaw
by
8.6k points

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