Given the equation -4Square root x-3=12, solve for x and identify if it is an extranous solution

asked Jul 28, 2018 168k views

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hope this helps.......

Fausto answered Jul 30, 2018

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-4sqrt(x)-3 = 12 -> sqrt(x) - 3 = -3 -> sqrt(x) = 0
so x = 0, only solution, no extraneous solution

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