Register
Find the vertex of the parabola y=-2x^2-8x-15
51.6k views
0 votes
Find the vertex of the parabola y=-2x^2-8x-15

User Alleo
by
6.0k points

2 Answers

2 votes
y = -2x^2 - 8x - 15 x = -b/2a
-(-8)/2(-2)
8/-4 = -2
y = -2(-2)^2 - 8(-2) - 15
y = -2(4) + (16) - 15
-8 + 16 -15
8 - 15 = -7
vertex: ( -2, -7)
User Fedeteka
by
6.3k points
2 votes

y=-2x^2-8x-15 \\ a=-2; \ b=-8; \ c=-15 \\ \\ x= (-b)/(2a)= (-(-8))/(2*(-2)) = (8)/(-4) =-2 \\ \\ y=-2x^2-8x-15 =-2(-2)^2-8(-2)-15 =-8+16-15=-7

Answer: (-2, -7)
User Shirkan
by
6.1k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.8m questions

9.0m answers

Other Questions

What is the least common denominator of the four fractions 20 7/10 20 3/4 18 9/10 20 18/25
Paul bought a student discount card for the bus. The card allows him to buy daily bus passes for $1.60. After one month, Paul bought 23 passes and spent a total of $45.80. How much did he spend on the
Which of the following comparisons is false? 5° c is warmer than 5°f. 15° c is cooler than 60° f. 30° c is warmer than 90° f. 35° c is cooler than 100° f.
What is 0.12 expressed as a fraction in simplest form
How would you subtract $150.00 and 144.001 to have left over money
Link Copied!