Question

Find the expression that represents the length of the hypotenuse of a right triangle whose legs measure m^2-n^2 and 2mn

Answer 1

It's d

Explanation:

I got it correct on the review

Answer 2

`\bf c^2=a^2+b^2\qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ ------\\ a=m^2-n^2\\ b=2mn \end{cases}\\\\\\ c^2=(m^2-n^2)^2+(\underline{2mn})^2 \\\\\\ c^2=m^4-2m^2n^2+n^4+\underline{2^2m^2n^2} \\\\\\ c^2=m^4-2m^2n^2+n^4+{4m^2n^2} \\\\\\ c^2=m^4+2m^2n^2+n^4\impliedby \textit{perfect square trinomial} \\\\\\ c^2=(m^2+n^2)^2\implies c=√((m^2+n^2)^2)\implies c=m^2+n^2`