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The line of best fit for this data is y = 0.864x + 31.15. Using this equation, to predict Christine’s Best Javelin Throw for the year 2005. Remember, x = 0 for 1997.
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Apr 1, 2018
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The line of best fit for this data is y = 0.864x + 31.15. Using this equation, to predict Christine’s Best Javelin Throw for the year 2005. Remember, x = 0 for 1997.
Mathematics
middle-school
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Salvatore
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Apr 2, 2018
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So you would look for years since 1997. That would be 8 years. Plug in 8 for x, and you get y = 0.864(8) + 31.15 which is equal to 38.062
I got that because I got this: 0.864*8 = 6.912, and then I added it to 31.15
Hope this helps.
Reaz
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Apr 5, 2018
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