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What is the slope of the line joining (10, 6) and (30, 10)? −5 negative start fraction one over five end fraction start fraction one over five end fraction 5
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What is the slope of the line joining (10, 6) and (30, 10)?

−5
negative start fraction one over five end fraction
start fraction one over five end fraction
5

User Bzin
by
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2 Answers

2 votes

\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 10}}\quad ,&{{ 6}})\quad % (c,d) &({{ 30}}\quad ,&{{ 10}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{10-6}{30-10}
User Maxian Nicu
by
7.1k points
6 votes
slope=(y2-y1)/(x2-x1), in this case:

slope=(10-6)/(30-10)

slope=4/20

slope=1/5
User Heliya Rb
by
7.6k points
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