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Simplify 9^2 over 9^7

User Quornian
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1/59049 !!!!!!!!!!!!!!!!!!!!
User Bazinga
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\( (9^2)/(9^7) \) simplifies to
\(9^(-5)\), representing the reciprocal of
\(9^5\). This follows the rule
\(a^m / a^n = a^(m-n)\), showcasing the exponent subtraction when dividing powers of the same base.

To simplify
\((9^2)/(9^7)\), apply the rule
\(a^m / a^n = a^(m-n)\) for the same base a. In this case, both bases are 9.


\[(9^2)/(9^7) = 9^(2-7) = 9^(-5)\]

So,
\((9^2)/(9^7) = (1)/(9^5)\) or
\(9^(-5)\).

The expression
\( (9^2)/(9^7) \) simplifies to
\( 9^(-5) \) using the rule
\(a^m / a^n = a^(m-n)\). This simplification represents the reciprocal of
\(9^5\), emphasizing the inverse relationship between the numerator and denominator.

Thus, the result is a fraction with the base 9 raised to the power of -5, indicating that the expression is equivalent to
\( (1)/(9^5) \). This showcases the mathematical principle of exponent subtraction when dividing powers of the same base, resulting in a concise and simplified form for the given expression.

User Sheldon Pinkman
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