Question

What is the equilibrium constant expression for the given reaction?

Answer 1

K = [CO₂]
.................
:)

Answer 2

Answer: Option (c) is the correct answer.

Step-by-step explanation:

At equilibrium the relationship expressed between the amounts of concentration of products and reactants in a reversible chemical reaction is known as equilibrium constant.

The concentration of solids and liquids is considered equal to 1 in equilibrium constant.

For example, in the given reaction
`CaCO_(3)(s) \rightleftharpoons CaO(s) + CO_(2)(g)`

Therefore, its equilibrium constant will be as follows.

`K_(eq) = ([CO_(2)][CaO])/(CaCO_(3))`

Here concentration of
`CaCO_(3)` and CaO is 1 as these are solids.

Thus, equilibrium constant expression will be as follows.

`K_(eq) = [CO_(2)]`