Question

Two consecutive integers have a sum of 513. Find the smaller of these two numbers

Answer 1

The smaller of the two consecutive numbers is 256.

Step-by-step explanation:

Let's denote the smaller of the two consecutive numbers as x. Since they are consecutive integers, the larger number would be x + 1. The sum of the two numbers is given as 513, so we can set up the following equation:

x + (x + 1) = 513

Combining like terms, we get 2x + 1 = 513. Subtracting 1 from both sides gives 2x = 512. Finally, dividing both sides by 2 gives us x = 256.

Therefore, the smaller of the two consecutive numbers is 256.

Answer 2

a+b=513
a=k
b=k+1
2k+1=513
2k=512
k=256

Answer:256