Question

Part A: Solve –mk – 120 > 95 for m. Show your work. (4 points) Part B: Solve 2c – 9f = 45 for f. Show your work. (6 points)

Answer 1

PART A:
Given -mk - 120 > 95.

Since we are solving for m, we take the other terms to the right hand side using arithmetic operations leaving only m in the left hand side.

To solve the ineaquality for m:
First, we collect like terms, i.e. we take -120 over to the right hand side to get
-mk > 95 + 120
-mk > 215

Next, we divide both sides by -k to get:

`m>(215)/(-k)`

`m>-(215)/(k)`


PART B:
Given 2c - 9f = 45.

Since we are solving for f, we take the other terms to the right hand side using arithmetic operations leaving only f in the left hand side.

To solve the equation for f:
First, we take 2c over to the right hand side to get
-9f = 45 - 2c

Next, we divide both sides by -9 to get:

`f=(45-2c)/(-9)`

The equation above can also be written in the following forms:

`f=-(45-2c)/(9)`
or

`f=(2c-45)/(9)`
or

`f=(2c)/(9)-5`
or

`f=-5+(2c)/(9)`