Question

What is the equation of the line with a slope of (3,4) that goes through the point (4,1) in slope/intercept form?

Answer 1

Hi there! :)

Explanation:

`slope=(Y_2-Y_1)/(X_2-X_1)=(RISE)/(RUN)`

`(1-4)/(4-3)=(-3)/(1)=-3`

Slope is -3.

Slope-intercept form:
`y=mx+b`

m: represents the slope.

b: represents the y-intercept.

`y-4=-3(x-3)`

`y-4=-3x+9`

`y=-3x+13`

Final answer is y=-3x+13

Hope this helps!

:)

:D

Have a nice day! :)

Answer 2

4-1= 3
3-4= -1 slope= -3

y-4=-3(x-3)
y-4=-3x+9
y=-3x +13