Question

Calculate the mass in grams of 0.800 mole of H2CO3. g

Answer 1

mH₂CO₃: (1g×2) + 12g + (16g×3) = 62 g/mol

1 mol --- 62g
0,8 mol -- X
X = 0,8×62
X = 49,6g

Answer 2

Step-by-step explanation:

It is known that number of moles is equal to the mass divided by molar mass of a substance.

Mathematically, No. of moles =
`\frac{mass}{\text{molar mass}}`

Since it is given that number of moles is 0.80 mol and molar mass of
`H_(2)CO_(3)` is 62.03 g/mol.

Therefore, we can conclude that mass of
`H_(2)CO_(3)` is as follows.

No. of moles =
`\frac{mass}{\text{molar mass}}`

0.80 mol =
`(mass)/(62.03 g/mol)`

mass = 49.62 g

Thus, we can conclude that mass in grams of 0.800 mole of
`H_(2)CO_(3)` is 49.62 g.