Question

Problem: An ice hockey player hits a puck of mass 0.15 kilograms with a force of 100 newtons in the horizontal direction. What is the acceleration produced by the force in the horizontal direction? Part A: Enter the variable symbol of the quantity you need to solve for. Use your keyboard and the keypad to enter your answer. Then click Done.

Answer 1

The acceleration of a 0.15 kg hockey puck when a force of 100 N is applied is calculated using Newton's second law (F = ma), yielding an acceleration of 666.67 m/s^2.

Step-by-step explanation:

The student's question involves calculating the acceleration of an ice hockey puck when a force is applied. According to Newton's second law of motion (F = ma), where F is force, m is mass, and a is acceleration, the variable we need to solve for is a (acceleration). To calculate this, we will use the formula a = F/m. Given that the force (F) is 100 newtons and the mass (m) of the puck is 0.15 kilograms, we can plug these values into the formula to get the acceleration (a).

Step-by-step calculation:

Write down the known values: F = 100 N, m = 0.15 kg.

Write down Newton's second law equation: a = F/m.

Calculate the acceleration: a = 100 N / 0.15 kg = 666.67 m/s2.

The acceleration produced by the 100 newton force in the horizontal direction is 666.67 m/s2.

Answer 2

It's a with the little x for all my plato users

and part b would be F with the little x =ma with the little x

and part c would be a with the little x = F with the little x over m

and part d would be a little x = 100 over 0.15

Step-by-step explanation: