Which graph shows inequality (y^2/2^2)-(x^2/2^2)>=1?

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asked Dec 8, 2018 71.6k views

1 Answer

Ghilas BELHADJ · Answer 1 · 2018-12-14T06:10:14+0000

The correct graph is D.

Step-by-step explanation:
Write the inequality as follows:

$( y^(2) )/(4) \geq (1+ ( x^(2) )/(4) )$

Then test values of x.
x=0: y=4 => y=+/- 2
x=1: y=5 => y= +/- 2.24

Only graph D behaves in this fashion.

Which graph shows inequality (y^2/2^2)-(x^2/2^2)>=1?

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