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How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia

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H₂SO₄ + 2NH₃ = (NH₄)₂SO₄

m{(NH₄)₂SO₄}=M{(NH₄)₂SO₄}n(H₂SO₄)

m{(NH₄)₂SO₄}=132.1g/mol*60.0mol=7926 g = 7.926 kg
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