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A bag contains 8 red marbles 3 blue marbles and 1 green marble find P not blue

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Sample space={8 R, 3B, 1 G} = 12 OUTCOMES

P( 1 blue) =3/12 = 1/4
P(NOT blue) = 1 - P(blue) = 1 - 1/4 = 3/4
User Andrew Shore
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Answer:


P(\text{Not blue})=(3)/(4)

Explanation:

We have been given that a bag contains 8 red marbles 3 blue marbles and 1 green marble. We are asked to find the probability of not getting a blue marble.

Probability of not getting a blue marble will be equal to probability of getting red marble plus probability of getting green marble.


P(Red)=(8)/(8+3+1)


P(Red)=(8)/(12)


P(Green)=(1)/(8+3+1)


P(Green)=(1)/(12)


P(\text{Not blue})=P(\text{Red})+P(\text{Green})


P(\text{Not blue})=(8)/(12)+(1)/(12)


P(\text{Not blue})=(8+1)/(12)


P(\text{Not blue})=(9)/(12)


P(\text{Not blue})=(3*3)/(3*4)


P(\text{Not blue})=(3)/(4)

Therefore, the probability of not getting a blue marble is
(3)/(4).

User Aequalsb
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