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The solids below are similar. give the scale factor, surface area ratio, and volume ratio.

The solids below are similar. give the scale factor, surface area ratio, and volume-example-1
User Kalpak
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Hello there. To solve this question, we'll have to remember some properties about scaling factor and ratios.

Given two solids that are similar:

We have to determine the scaling factor, the surface area and volume ratios.

First, the scaling factor, in the case of spheres, is the ratio between their radius.

In this case, we determine each ratio using the formula for the volume:


V=(4\pi\cdot R^3)/(3)

For a sphere with radius R.

In our case, say the smaller sphere has radius r and the larger sphere has radius R.

Hence we have that:


V(r)=250=(4\pi\cdot r^3)/(3)

Multiply both sides of the equation by a factor of 3/4pi


r^3=250\cdot(3)/(4\pi)=(375)/(2\pi)

Take the cube root on both sides of the equation


r=\sqrt[3]{(375)/(2\pi)}

We're not using an approximation here because we'll need this value until the end.

Now, for the sphere with radius R, we have


V(R)=686=(4\pi \cdot R^3)/(3)

Multiply both sides by 3/4pi


R^3=686\cdot(3)/(4\pi)=(1029)/(2\pi)

Take the cube root on both sides of the equation


R=\sqrt[3]{(1029)/(2\pi)}

The scaling factor is given by:


(R)/(r)=\frac{\sqrt[3]{(1029)/(2\pi)}}{\sqrt[3]{(375)/(2\pi)}}=\sqrt[3]{(343)/(125)}

Now, we can find an approximation for it as:


\text{ Scaling factor }=1.4

In fact it is exact.

Now, to find the surface area and volume ratios, we use the formulas to show that:

The surface area of a sphere with radius R is


S=4\pi\cdot R^2

Hence the ratio is


\text{ Surface area ratio }=(4\pi R^2)/(4\pi r^2)=\left((R)/(r)\right)^2

Plugging the solution we found, we get


1.4^2=1.96

In a same manner for a volume, we get


\text{ Volume ratio }=((4\pi R^3)/(3))/((4\pi r^3)/(3))=\left((R)/(r)\right)^3

Hence we get


1.4^3=2.744

These are the answers to this question.

The solids below are similar. give the scale factor, surface area ratio, and volume-example-1
User SatheeshJM
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