Final answer:
The domain of the function f(x) = (1/6)^x + 2 is all real numbers, and the range is all real numbers greater than or equal to 2.
Step-by-step explanation:
The domain of the function f(x) = (1/6)^x + 2 is the set of all real numbers. Since the base of the exponent is positive and not equal to 1, the function is defined for all values of x.
The range of the function f(x) = (1/6)^x + 2 is the set of all real numbers greater than or equal to 2. The exponential part of the function, (1/6)^x, is always positive and decreases as x increases. Therefore, the minimum value of the function is 2 when x is negative infinity.