line AB passes through points A(-6,6) and B(12,3) if the equation of the line is written in slope intercept form

asked Jan 6, 2018 104k views

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y=(-1/6)x+5
m=(y2-y1)/(x2-x1)
m=(3-6)/(12-(-6))
m=(-3)/(18)
m=-1/6
y=mx+b
y=(-1/6)x+b
6=(-1/6)(-6)+b
6=1+b
b=5
y=(-1/6)x+5

Alexojegu answered Jan 10, 2018

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