Question

When the product of 6 and the square of a number is increased by 5 times the number, the result is 4. Select all the values that the number could be

Answer 1

hello : let : x this number
6x²-5x =4
6x² -5x -4 = 0
the discriminant : Δ = b²-4ac a = 6 b= -5 c = -4
Δ = (-5)²-4(6)(-4) =25 +96 = 121 = 11²
x1 = (5-11) /12 = -1/2
x2 = (5+11)/12 =16/12=4/3

Answer 2

Since the other question is hard to read the answer is

-4/3 and 1/2

Explanation:

Just did it on edge