Question

Which function in vertex form is equivalent to f(x) = x2 + 6x + 3?

Answer 1

(-3, -6)
(sorry, the other calculator does the answers, but not the one i'm using right now!)

Answer 2

`y=(x+3)^(2)-6`

Explanation:

Let's find the answer using the following method:

The original quadratic function is
`f(c)=x^(2)+6x+3`

The vertex form of a quadratic equation is:

`y=(x-h)^(2)+k`

where (h,k) is the vertex which can be found as:

`h=(-b)/(2a) =(-6)/(2*1)=-3\\h=f(h)=(-3)^(2)+(6*(-3))+3 = -6`

So the vertex form is:

`y=(x+3)^(2)-6`