How many moles of oxygen can be formed from 250 grams of aluminum oxide

Question

asked Apr 26, 2018 209k views

1 Answer

Trevor Johnson · Answer 1 · 2018-05-01T07:18:02+0000

2Al₂O₃ = 4Al + 3O₂

M(A₂O₃)=101.96 g/mol
m(Al₂O₃)=250 g

n(O₂)=3m(Al₂O₃)/{2M(Al₂O₃)}

n(O₂)=3*250/{2*101.96}=3.678 mol