Question

Find the lowest common denominator of the following fractions.

y+5/6y^2-6 and 7/8y+8

A. 24y 2
B. 24(y 2 - 1)
C. 24(y 2 - 1)(y + 1)

Answer 1

I believe the answer is B, 24(y^2 - 1)

Answer 2

(B)
`24(y^2-1)`

Explanation:

Given: The given following fractions are:

`(y+5)/(6y^2-6)` and
`{(7)/(8y+8)}`

To find: The lowest common denominator of the given fractions.

Solution: The given following fractions are:

`(y+5)/(6y^2-6)` and
`{(7)/(8y+8)}`

Simplifying the above fractions, we get

`(y+5)/(6(y^2-1))` and
`(7)/(8(y+1))`

Now, the lowest common denominator of the above fractions is:

`24(y+1)(y-1)`

=
`24(y^2-1)` (using identity
`a^2-b^2=(a+b)(a-b)`)

Hence, option (B) is correct