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2 votes
Find the lowest common denominator of the following fractions.

y+5/6y^2-6 and 7/8y+8

A. 24y 2
B. 24(y 2 - 1)
C. 24(y 2 - 1)(y + 1)

User Mtkale
by
7.4k points

2 Answers

4 votes
I believe the answer is B, 24(y^2 - 1)
User Nandita
by
8.8k points
3 votes

Answer:

(B)
24(y^2-1)

Explanation:

Given: The given following fractions are:


(y+5)/(6y^2-6) and
{(7)/(8y+8)}

To find: The lowest common denominator of the given fractions.

Solution: The given following fractions are:


(y+5)/(6y^2-6) and
{(7)/(8y+8)}

Simplifying the above fractions, we get


(y+5)/(6(y^2-1)) and
(7)/(8(y+1))

Now, the lowest common denominator of the above fractions is:


24(y+1)(y-1)

=
24(y^2-1) (using identity
a^2-b^2=(a+b)(a-b))

Hence, option (B) is correct

User Arun Krishnan
by
8.9k points
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