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6 votes
Find the integral:

∫−20(x+5)dx

1 Answer

8 votes

Answer:


-20\left((x^2)/(2)+5x\right)+C

Explanation:


\int \:-20\left(x+5\right)dx


\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx


-20\cdot \int \:x+5dx


\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx


-20\left(\int \:xdx+\int \:5dx\right)


=-20\left((x^2)/(2)+5x\right)


\mathrm{Add\:a\:constant\:to\:the\:solution}


=-20\left((x^2)/(2)+5x\right)+C

User Dmitry Guselnikov
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