Question

You randomly pull a scrap from a bag of scraps. The bag has 4 greenscraps, 1 blue scrap, 4 black scraps, and 1 yellow scrap.What is the probability of drawing a green scrap?TY2X² f(x) n/X X₁XXXXTU

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

bag of scraps:

green scraps = 4

blue scrap = 1

black scraps = 4

yellow scraps = 1

Step 01:

probability:

p(event) = favorable outcomes / total outcomes

total outcomes = 4 + 1 + 4 + 1 = 10

p (green scrap):

p (green scrap) = 4 / 10 = 2 / 5

p (against drawing a green scrap):

p (against drawing a green scrap) = 1 - 2/5 = 3/5

The answer is:

p (green scrap) = 2/5

p (against drawing a green scrap) = 3/5