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33 votes
33 votes
brand A granola is 25% nuts and dried fruit and brand B granola is 10% nuts and dried fruit. how much of sweet item A and sweet item B should be mixed to form a 20lb batch of sweets that is 13%nuts and dried fruit?

User Jim Chertkov
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1 Answer

22 votes
22 votes

Solution:

Let A represent brand A, and B represent brand B. This implies that


\begin{gathered} A\Rightarrow brand\text{ A} \\ B\Rightarrow brand\text{ B} \end{gathered}

Given that A is 25% nuts and dried fruit, and B is 10% nuts and dried fruit, this implies that the total mixture is expressed as


Total\text{ mixture = }25A+20B

If A and B are mixed to form a 20 lb batch of sweet that is 13% nuts and dried fruit, thus implies that


\begin{gathered} Total\text{ mixture = 13\lparen20\rparen=260} \\ thus, \\ 25A+20B=260\text{ ----- equation 1} \end{gathered}

Also, given that A and B are mixed to form 20 lb batch, this implies that


A+B=20\text{ ----- equation 2}

To solve the amount of A and B, we solve the equations simultaneously.

Step 1: From equation 2, make B the subject of the equation.

Thus,


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User Mtk
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