Question

Accurately calculate the concentration of the diluted solution starting with the concentration of the stock fe(no3)3 solution (0.2 m).

Answer 1

Ans: 25 mM

For example, suppose we take the following concentrations:

Diluted Fe
`(NO_(3))_(3)` =1 ml

1 M KSCN = 5 ml

0.1 M HN
`O_(3)` = 2 ml
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Then, total volume = 8 ml

Now,
final concentration of diluted Fe
`(NO_(3))_(3)` =
`(Concentration - of Fe(NO_(3))_(3)*Volume of Fe(NO_(3))_(3))/(Total Volume) \\ \\`

given stock solution is 0.2 M

Thus, concentration of diluted solution =
`(0.2*1)/(8) = 0.025 M = 25 milli M`