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What mass of hydrogen gas can be produced by 6.0 mol of aluminum with hydrochloric acid?

User Tahesha
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2Al + 6HCl = 2AlCl₃ + 3H₂

m(H₂)=3M(H₂)n(Al)/2

m(H₂)=3*2.0g/mol*6.0mol/2=18.0 g
User Mardon
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