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If a cell has a volume of 3nm, what are the surface area and the volume of the cell?
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May 4, 2018
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If a cell has a volume of 3nm, what are the surface area and the volume of the cell?
Mathematics
high-school
Vishnu Jayanand
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Vishnu Jayanand
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A cell has a radius: r = 3 nmThe surface area of a cell:A = 4 r² π = 4 · 3² π = 4 · 9 π =
36 π nm²
The volume of a cell:V = 4/3 r³ π = 4/3 · 3³ π = 4 · 9 π =
36 π nm³
Answer: The surface area is 36 π nm² and the volume is 36 π nm³.
Jmcastel
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May 9, 2018
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Jmcastel
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