Question

The Ksp of beryllium hydroxide, Be(OH)2, is 6.92 × 10-22. Calculate the solubility of this compound in g/L.

Answer 1

Solubility product constants are values to describe the saturation of ionic compounds with low solubility. It is represented by Ksp and is the product of the concentration of the dissolved ions to the power of its stoichiometric coefficient. We do as follows:

Be(OH)2 = Be2+ + 2OH-

Ksp = [Be2+][OH-]^2
6.92 × 10^-22 = x(2x)^2
x = 5.57x10^-8 mol /L

[Be(OH)2] = x = 5.57x10^-8 mol /L = 2.397x10^-6 g/L