Question

What volume of a 1.50 m hcl solution should you use to prepare 2.00 l of a 0.100 m hcl solution?

Answer 1

(2.00 L) x (0.100 M HCl) / (1.50 M HCl) = 0.133 L

Answer 2

Answer : The volume of a 1.50 M HCl solution use should be 0.133 L

Explanation :

Using neutralization law,

`M_1V_1=M_2V_2`

where,

`M_1` = concentration of HCl solution = 1.50 M

`M_2` = concentration of another HCl solution = 0.100 M

`V_1` = volume of HCl solution = ?

`V_2` = volume of another HCl solution = 2.00 L

Now put all the given values in the above law, we get:

`1.50M* V_1=0.100M* 2.00L`

`V_1=0.133L`

Therefore, the volume of a 1.50 M HCl solution use should be 0.133 L