Answer:
The correct options are A, D and E.
Explanation:
We are given the function
![y=\sqrt[3]{x-1} +2](https://img.qammunity.org/2018/formulas/mathematics/middle-school/hbvrpd94bo3wkrbwcdfow8ufiyonuhnzlf.png)
From the graph below, we see that,
Domain and range of the function is the set of all real numbers.
As y-intercept is the point where the graph of the function crosses y-axis.
That is, y-intercept is obtained when x= 0.
So, on substituting, we have,
![y=\sqrt[3]{0-1} +2](https://img.qammunity.org/2018/formulas/mathematics/middle-school/fdki4cwbtuwj042lz08cb0jera21yk1lca.png)
i.e.

i.e. y= 1
Thus, the y-intercept is (0,1).
Also, x-intercept is the point where the graph of the function crosses x-axis.
That is, x-intercept is obtained when y= 0.
So, on substituting, we have,
![0=\sqrt[3]{x-1} +2](https://img.qammunity.org/2018/formulas/mathematics/middle-school/r18zldicc4adyyfy7canp8f2w3d7xs6d90.png)
i.e.
![-2=\sqrt[3]{x-1}](https://img.qammunity.org/2018/formulas/mathematics/middle-school/1c533oryrddpd86jhrrg4jcm7gvd6zp1i2.png)
i.e.

i.e. x= -7
Thus, the x-intercept is (-7,0).
Hence, the correct options for the function are,
A. The graph has a domain of all real numbers.
D. The graph has a y-intercept at (0, 1)
E. The graph has an x-intercept at (–7, 0).