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A spring that has a spring constant of 1400 N/m is stretched to a length of 2.5 m. If the normal length of the spring is 1.0 m, how much elastic potential energy is stored in the spring?
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A spring that has a spring constant of 1400 N/m is stretched to a length of 2.5 m. If the normal length of the spring is 1.0 m, how much elastic potential energy is stored in the spring?

User Almaz
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2 Answers

5 votes

Answer:1575 J

Explanation:Just took the test.

User Vadimchin
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7.8k points
4 votes
Elastic potential energy is the energy that is stored from the deformation of an object that is elastic like a spring. It is calculated by one half of the product of the spring constant and the square of the displacement. We do as follows:

PE = kx^2/2
PE = (1400)(2.5-1)^2 / 2
PE = 1575 J
User Hangster
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7.7k points
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