Question

What is the equation in point−slope form of the line passing through (0, 6) and (1, 3)?

A) (y-3)= -3(x-1)
B) (y+3)=3(x+1)
C) (y+3)=-3(x+1)
D) (y-3)=3(x+6)

Answer 1

(0,6)(1,3)
slope(m) = (3 - 6) / (1 - 0) = -3

y - y1 = m(x - x1)
slope(m) = -3
(1,3)...x1 = 1 and y1 = 3
now we sub
y - 3 = -3(x - 1) <===