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What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare

100.0 milliliters of a 0.50 M acetic acid solution?

1 Answer

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n(CH₃COOH)=c₁v₁=c₂v₂

c₁=2.5 mol/L
c₂=0.50 mol/L
v₁-?
v₂=100.0 mL=0.1000L

v₁=c₂v₂/c₁

v₁=0.50*0.1000/2.5=0.02 L = 20 mL
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