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what is the probability that a point in the figure chosen at random will be in the shaded portion of the figure

what is the probability that a point in the figure chosen at random will be in the-example-1
User Prevok
by
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1 Answer

16 votes
16 votes
Answer:

Probability = 48% ( to the nearet percent)

Explanations:

The entire shape is a rectangle of:

length = 4

width = 3

Area of the rectangle = 4 x 3

Area of the rectangle = 12

Area of the entire shape = 12

There are two circles in the rectangle, each of radius, r = 1

Area of a circle = πr²

Area of the circle = 3.142 x 1²

Area of the circle = 3.142

Since there are two circles in the shape

Total area of the circular portion = 2 x 3.142

Total area of the circular portion = 6.284

Area of the shaded portion = Area of the entire shape - Area of the circular portion

Area of the shaded portion = 12 - 6.284

Area of the shaded portion = 5.716

Probability that a point in the figure chosen at random will be in the shaded portio of the figure:

Probability = (Area of the shaded region) / (Area of the entire shape)

Probability = 5.716 / 12

Probability = 0.476

Probability = 0.48 x 100%

Probability = 48% ( to the nearet percent)

User Riadh Gomri
by
3.3k points