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Find the geometric sum: 12 + 36 + 108 + … + 78,732. 39,360 118,092 1,062,876 354,288
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Nov 19, 2018
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Find the geometric sum: 12 + 36 + 108 + … + 78,732. 39,360 118,092 1,062,876 354,288
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Sanal S
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This is a geometric sequence with an initial term of 12 and a common ratio of 3.
The rule for a geometric sequence is:
a(n)=ar^(n-1) we are told that the last term is 78732 so we can find the number of terms in the sequence...
78732=12(3)^(n-1) divide both sides by 12
6561=3^(n-1) take the natural log of both sides
ln6561=(n-1)ln3 divide both sides by ln3
ln6561/ln3=n-1 add 1 to both sides
ln6561/ln3 +1=n
9=n so there are 9 terms in the sequence.
The sum of any geometric sequence is:
s(n)=a(1-r^n)/(1-r), in this case a=12, r=3, and n=9 so
s(9)=12(1-3^9)/(1-3)
s(9)=12(1-19683)/(-2)
s(9)=-6(-19682)
s(9)=118092
Unni
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Nov 26, 2018
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Unni
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