Question

The molar heat of fusion for water is 6.01 kJ/mol. How much energy is released when 36.8 g of water freezes at its freezing point? Use mc030-1.jpg.

Answer 1

=(Heat of fusion)(mass/molar mass)
=(6.01)(36.8/18.02)
=12.27347392 kilojoules

Answer 2

The heat released = 12.2 kJ

Step-by-step explanation:

The heat of fusion of water = 6.01kJ/mol

Molar mass of water = 18g

Thus we can say that

The energy released when 18g (molar mass of water) freeze = 6.01kJ

thus the heat released when one gram of water freeze

=
`(6.01)/(18)=0.3339kJ`

The heat released when 36.5g of water freeze = 0.3339 X 36.5 = 12.187 kJ