Question

Please I need help!!!

Answer 1

Isolate y in the first equation.


`2y = 10x`


`y = 5x`

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Then plug this into the second equation


`(x^2)/(64)-(y^2)/(36) = 1`


`(x^2)/(64)-((y)^2)/(36) = 1`


`(x^2)/(64)-((5x)^2)/(36) = 1`


`(x^2)/(64)-(25x^2)/(36) = 1`

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So the final answer is choice A