Question

Find the perimeter of the shape below:

Answer 1

add all sides


use distance formula to fnd distance: sqrt((x1-x2)^2+(y1-y2)^2)
if is wrong,i'm sorry,i think this is right

Answer 2

Perimeter = 13.27 unit

Explanation:

We have to find the perimeter of the shape given in the figure.

Coordinates of J are ( -3, 4 ) and K are (-1, 6)

Then JK =
`\sqrt{(x-x')^(2)+(y-y')^(2)}`

=
`√((-3+1)^2+(6-4)^2)`

=
`√(4+4)`

=
`2√(2)`

Coordinates of K are (-1,6) and for ∠ are (1, 1)

KL =
`√((1+1)^2+(1-6)^2)`

=
`√(2^2+5^2)`

=
`√(29)`

Coordinates of M are (-1, 3) and of ∠ are (1, 1)

∠M =
`√((1+1)^2+(1-3)^2)`

=
`√(4+4)`

=
`2√(2)`

Coordinates of M are (-1, 3) and J are (-3, 4)

MJ =
`√((-1+3)^2+(3-4)^2)`

=
`√(4+1)`

=
`√(5)`

Then perimeter = JK + KL + LM + MJ

=
`2√(2)` +
`√(29)` +
`2√(2)` +
`√(5)`

=
`4√(2)` +
`√(29)` +
`√(5)`

= 5.66 + 5.38 + 2.24 = 13.27