Question

Which function in vertex form is equivalent to f(x)=4+x^2-2x

A) f(x)=(x-1)^2+3
B) f(x)=(x-1)^2+5
C) f(x)=(x+1)^2+3
D) f(x)=(x+1^2+5

Answer 1

f(x)=4-2x+x^2
=4-1+1-x-x+x^2
=3+(1-x) - x(1-x)
= 3+(1-x) (1-x)
= 3 + (1 - x)^2
f(x) = (1 - x)^2 + 3