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What are the period and amplitude of the function y 2sin4?

2 Answers

2 votes
hello :
note :

y = A sin(Bx + C) + D

amplitude is A period is 2π/B
in this exercice :
2sin(4x)
amplitude is 2 period is 2π/4= π/2

User David Williames
by
8.9k points
5 votes

Answer:

Explanation:

Alright, lets get started.

The given function is :


y=2sin(4x)

The standard form of sin function is given as :


y=asin(bx+c)

So when we compare our given function with standard one, we have b as 4

The formula of period is :
(2\pi )/(b)

Plugging the value of b as 4 in formula of period, we will have

Period =
(2\pi )/(4)=(\pi )/(2)

Amplitude is given as a which is 2

So the answer is period
(\pi )/(2) and amplitde 2 : Answer

Hope it will help :)

User Shlomi Komemi
by
8.3k points

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