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How many moles of PCl5 can be produced from 22.0 g of P4 (and excess Cl2)?

1 Answer

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The balanced chemical reaction is written as:

P4 + 10Cl2 = 4PCl5

To determine the moles of PCl5 produced, we use the initial amount of the limiting reactant which is P4 and the relation from the reaction. We do as follows:

22.0 g P4 ( 1 mol / 123.90 g ) ( 4 mol PCl5 / 1 mol P4 ) = 0.7103 mol PCl5 produced
User Yoges Nsamy
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