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Potassium fluoride (KF, a salt, has a molecular weight of 58.10 grams. How many grams would be needed to make 1.0 liter of 5.0 molar salt solution?
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Potassium fluoride (KF, a salt, has a molecular weight of 58.10 grams. How many grams would be needed to make 1.0 liter of 5.0 molar salt solution?

User Steve Ganem
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For Odyssey ware users the answer is 291 g

Step-by-step explanation:

User GordonM
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The concentration of the solution is 5.0 molar, which is 5.0 mole/L.  So in the 1.0 L of 5.0 molar KF salt solution, the moles of KF is 5.0molar*1.0L=5.0 mole. The molecular weight of KF is given in the question as 58.10 gram/mole, so the grams of KF is 58.10 gram/mole * 5.0 mole = 290.5 gram.
User Ramesh Paul
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