Question

A 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, what was the initial temperature of the copper piece?Specific heat of copper = 0.39 J/g °C 322 °C 345 °C 356 °C 364 °C

Answer 1

`T_i\text{ = 364}\degree C`

Step-by-step explanation:

Here, we want to get the initial temperature of the copper piece

Mathematically:

`Heat\text{ loss by copper = Heat gained by water}`

The amount of heat lost or gained by any substance can be calculated as:

`q\text{ = mc}\Delta T`

where:

m represents the mass

c represents the specific heat capacity (heat capacity of water is 4.184 J/g.C)

delta T represents the temperature change

Substituting the values, we have it that:

`240*0.39\text{ }*\text{ \lparen T}_i-42)\text{ = 400}*4.184\text{ }*(42-24)`
`\begin{gathered} 93.6(T_i-42)\text{ = 30124.8} \\ T_i-42\text{ = }(30124.8)/(93.6) \\ \\ T_I-42\text{ = 321.85} \\ T_i\text{ =321.85 + 42} \\ T_i\text{ = 364}\degree C \end{gathered}`