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Show all worked identify the asymptotes and state the end behavior of the function F(x)=6x over x-36

User Surbhi
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1 Answer

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17 votes

Solution

Asymptote:

Vertical Asymptote

- The vertical asymptotes of a rational function are determined by the denominator expression.

- The expression given is:


f(x)=(6x)/(x-36)

- The denominator of (x- 36) determines the asymptote line.

- The vertical asymptote defines where the rational function isundefined. Iin order for a rational function to be undefined, its denominator must be zero.

- Thus, we can say:


\begin{gathered} x-36=0 \\ Add\text{ 36 to both sides} \\ \\ \therefore x=36 \end{gathered}

- Thus, the vertical asymptote is


x=36

Horizontal Asymptote:

- The horizontal asymptote exists in two cases:

1. When the highest degree of the numerator is less han the degree of the demnominator. In this case, the horizontal asymptote is y = 0

2. When the highest degee sof the numerator and tdenominator are the same. In this case, the horizontal asymptote is


\begin{gathered} y=(N)/(D) \\ where, \\ N=\text{ Coefficient of the highest degree of the numerator} \\ D=\text{ Coefficient of the highest degree of the denominator} \end{gathered}

- For our question, we can see that the highest degrees of the numerator and denominator are the same. Thus, we have the Horizontal Asymptote to be:


y=(6)/(1)=6

End behavior:

- The end behavior is examining the y-values of the function as x tendsto negative and positive infinity.

- Thus, we have that:


\begin{gathered} f(x)=(6x)/(x-36) \\ \\ \text{ Divide top and bottom by }x \\ f(x)=(6x)/(x-36)*(x)/(x) \\ \\ f(x)=((6x)/(x))/((x-36)/(x))=(6)/(1-(36)/(x)) \\ \\ As\text{ }x\to-\infty \\ f(-\infty)=(6)/(1-(36)/(-\infty))=(6)/(1+(36)/(\infty))=(6)/(1+0)=6 \\ \\ \text{ Thus, we can say: }x\to-\infty,f(x)\to6 \\ \\ Also, \\ As\text{ }x\to\infty \\ f(\infty)=(6)/(1-(36)/(\infty))=(6)/(1-0)=6 \\ \\ \text{ Thus, we can also say: }x\to\infty,f(x)\to6 \end{gathered}

Final Answers

Asymptotes:


\begin{gathered} \text{ Vertical:} \\ x=36 \\ \\ \text{ Horizontal:} \\ y=6 \end{gathered}

End behavior:


\begin{gathered} As\text{ }x\to-\infty,f(x)\to6 \\ \\ As\text{ }x\to\infty,f(x)\to6 \end{gathered}

User Paresh Barad
by
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