Final answer:
a. The half-life of Moskiller is approximately 1.4 years using the rule of 70. b. After 6 years, approximately 305,260 mosquitoes would remain assuming a steady rate of decrease.
Step-by-step explanation:
a. The rule of 70 states that the number of years it takes for a quantity to double or halve can be approximated by dividing 70 by the percentage rate of growth or decline. In this case, the mosquitoes decrease by 50% per year. So, to find the half-life of Moskiller, we divide 70 by 50, which equals 1.4 years.
b. Assuming the rate is steady, we can use the half-life to find the number of mosquitoes remaining after 6 years. Since the half-life is 1.4 years, after 6 years, the number of half-lives would be 6 divided by 1.4, which is approximately 4.29. Using the formula N = N0 * (1/2)^(t/h), where N0 is the initial number of mosquitoes, t is the number of years, and h is the half-life, we can calculate the number of mosquitoes remaining as N = 2,450,000 * (1/2)^(4.29) ≈ 305,260.